Format and remove 09.5.md spaces

zh/09.5.md

@@ -9,20 +9,20 @@
 Go语言对这三种加密算法的实现如下所示：
 ```Go
 
-	//import "crypto/sha256"
+//import "crypto/sha256"
-	h := sha256.New()
+h := sha256.New()
-	io.WriteString(h, "His money is twice tainted: 'taint yours and 'taint mine.")
+io.WriteString(h, "His money is twice tainted: 'taint yours and 'taint mine.")
-	fmt.Printf("% x", h.Sum(nil))
+fmt.Printf("% x", h.Sum(nil))
 
-	//import "crypto/sha1"
+//import "crypto/sha1"
-	h := sha1.New()
+h := sha1.New()
-	io.WriteString(h, "His money is twice tainted: 'taint yours and 'taint mine.")
+io.WriteString(h, "His money is twice tainted: 'taint yours and 'taint mine.")
-	fmt.Printf("% x", h.Sum(nil))
+fmt.Printf("% x", h.Sum(nil))
 
-	//import "crypto/md5"
+//import "crypto/md5"
-	h := md5.New()
+h := md5.New()
-	io.WriteString(h, "需要加密的密码")
+io.WriteString(h, "需要加密的密码")
-	fmt.Printf("%x", h.Sum(nil))
+fmt.Printf("%x", h.Sum(nil))
 
 ```
 单向哈希有两个特性：
@@ -44,25 +44,25 @@ Go语言对这三种加密算法的实现如下所示：
 
 ```Go
 
-	//import "crypto/md5"
+//import "crypto/md5"
-	//假设用户名abc，密码123456
+//假设用户名abc，密码123456
-	h := md5.New()
+h := md5.New()
-	io.WriteString(h, "需要加密的密码")
+io.WriteString(h, "需要加密的密码")
 
-	//pwmd5等于e10adc3949ba59abbe56e057f20f883e
+//pwmd5等于e10adc3949ba59abbe56e057f20f883e
-	pwmd5 :=fmt.Sprintf("%x", h.Sum(nil))
+pwmd5 :=fmt.Sprintf("%x", h.Sum(nil))
 
-	//指定两个 salt： salt1 = @#$%   salt2 = ^&*()
+//指定两个 salt： salt1 = @#$%   salt2 = ^&*()
-	salt1 := "@#$%"
+salt1 := "@#$%"
-	salt2 := "^&*()"
+salt2 := "^&*()"
 
-	//salt1+用户名+salt2+MD5拼接
+//salt1+用户名+salt2+MD5拼接
-	io.WriteString(h, salt1)
+io.WriteString(h, salt1)
-	io.WriteString(h, "abc")
+io.WriteString(h, "abc")
-	io.WriteString(h, salt2)
+io.WriteString(h, salt2)
-	io.WriteString(h, pwmd5)
+io.WriteString(h, pwmd5)
 
-	last :=fmt.Sprintf("%x", h.Sum(nil))
+last :=fmt.Sprintf("%x", h.Sum(nil))
 
 ```
 在两个salt没有泄露的情况下，黑客如果拿到的是最后这个加密串，就几乎不可能推算出原始的密码是什么了。
@@ -79,7 +79,7 @@ Go语言对这三种加密算法的实现如下所示：
 目前Go语言里面支持的库http://code.google.com/p/go/source/browse?repo=crypto#hg%2Fscrypt
 ```Go
 
-	dk := scrypt.Key([]byte("some password"), []byte(salt), 16384, 8, 1, 32)
+dk := scrypt.Key([]byte("some password"), []byte(salt), 16384, 8, 1, 32)
 ```
 通过上面的的方法可以获取唯一的相应的密码值，这是目前为止最难破解的。