update the code style
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14
en/04.5.md
14
en/04.5.md
@@ -4,12 +4,16 @@ Suppose you have a website like Instagram and you want users to upload their bea
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You have to add property `enctype` to the form that you want to use for uploading photos. There are three possible values for this property:
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You have to add property `enctype` to the form that you want to use for uploading photos. There are three possible values for this property:
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```
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application/x-www-form-urlencoded Transcode all characters before uploading (default).
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application/x-www-form-urlencoded Transcode all characters before uploading (default).
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multipart/form-data No transcoding. You must use this value when your form has file upload controls.
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multipart/form-data No transcoding. You must use this value when your form has file upload controls.
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text/plain Convert spaces to "+", but no transcoding for special characters.
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text/plain Convert spaces to "+", but no transcoding for special characters.
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```
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Therefore, the HTML content of a file upload form should look like this:
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Therefore, the HTML content of a file upload form should look like this:
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```
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<html>
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<html>
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<head>
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<head>
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<title>Upload file</title>
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<title>Upload file</title>
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@@ -22,9 +26,12 @@ Therefore, the HTML content of a file upload form should look like this:
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</form>
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</form>
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</body>
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</body>
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</html>
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</html>
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```
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We need to add a function on the server side to handle this form.
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We need to add a function on the server side to handle this form.
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```
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http.HandleFunc("/upload", upload)
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http.HandleFunc("/upload", upload)
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// upload logic
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// upload logic
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@@ -56,6 +63,8 @@ We need to add a function on the server side to handle this form.
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io.Copy(f, file)
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io.Copy(f, file)
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}
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}
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}
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}
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```
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As you can see, we need to call `r.ParseMultipartForm` for uploading files. The function `maxMemory` argument. After you call `ParseMultipartForm`, the file will be saved in the server memory with `maxMemory` size. If the file size is larger than `maxMemory`, the rest of the data will be saved in a system temporary file. You can use `r.FormFile` to get the file handle and use `io.Copy` to save to your file system.
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As you can see, we need to call `r.ParseMultipartForm` for uploading files. The function `maxMemory` argument. After you call `ParseMultipartForm`, the file will be saved in the server memory with `maxMemory` size. If the file size is larger than `maxMemory`, the rest of the data will be saved in a system temporary file. You can use `r.FormFile` to get the file handle and use `io.Copy` to save to your file system.
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@@ -69,11 +78,13 @@ We use three steps for uploading files as follows:
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The file handler is the `multipart.FileHeader`. It uses the following struct:
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The file handler is the `multipart.FileHeader`. It uses the following struct:
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```
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type FileHeader struct {
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type FileHeader struct {
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Filename string
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Filename string
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Header textproto.MIMEHeader
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Header textproto.MIMEHeader
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// contains filtered or unexported fields
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// contains filtered or unexported fields
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}
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}
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```
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@@ -83,6 +94,7 @@ Figure 4.5 Print information on server after receiving file.
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I showed an example of using a form to a upload a file. We can impersonate a client form to upload files in Go as well.
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I showed an example of using a form to a upload a file. We can impersonate a client form to upload files in Go as well.
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```
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package main
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package main
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import (
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import (
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@@ -142,6 +154,8 @@ I showed an example of using a form to a upload a file. We can impersonate a cli
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filename := "./astaxie.pdf"
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filename := "./astaxie.pdf"
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postFile(filename, target_url)
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postFile(filename, target_url)
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}
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}
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```
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The above example shows you how to use a client to upload files. It uses `multipart.Write` to write files into cache and sends them to the server through the POST method.
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The above example shows you how to use a client to upload files. It uses `multipart.Write` to write files into cache and sends them to the server through the POST method.
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