update the code style

This commit is contained in:
astaxie
2015-04-02 13:22:13 +08:00
committed by James Miranda
parent 7fda55b543
commit efb458cd1b

View File

@@ -4,12 +4,16 @@ Suppose you have a website like Instagram and you want users to upload their bea
You have to add property `enctype` to the form that you want to use for uploading photos. There are three possible values for this property: You have to add property `enctype` to the form that you want to use for uploading photos. There are three possible values for this property:
```
application/x-www-form-urlencoded Transcode all characters before uploading (default). application/x-www-form-urlencoded Transcode all characters before uploading (default).
multipart/form-data No transcoding. You must use this value when your form has file upload controls. multipart/form-data No transcoding. You must use this value when your form has file upload controls.
text/plain Convert spaces to "+", but no transcoding for special characters. text/plain Convert spaces to "+", but no transcoding for special characters.
```
Therefore, the HTML content of a file upload form should look like this: Therefore, the HTML content of a file upload form should look like this:
```
<html> <html>
<head> <head>
<title>Upload file</title> <title>Upload file</title>
@@ -22,9 +26,12 @@ Therefore, the HTML content of a file upload form should look like this:
</form> </form>
</body> </body>
</html> </html>
```
We need to add a function on the server side to handle this form. We need to add a function on the server side to handle this form.
```
http.HandleFunc("/upload", upload) http.HandleFunc("/upload", upload)
// upload logic // upload logic
@@ -56,6 +63,8 @@ We need to add a function on the server side to handle this form.
io.Copy(f, file) io.Copy(f, file)
} }
} }
```
As you can see, we need to call `r.ParseMultipartForm` for uploading files. The function `maxMemory` argument. After you call `ParseMultipartForm`, the file will be saved in the server memory with `maxMemory` size. If the file size is larger than `maxMemory`, the rest of the data will be saved in a system temporary file. You can use `r.FormFile` to get the file handle and use `io.Copy` to save to your file system. As you can see, we need to call `r.ParseMultipartForm` for uploading files. The function `maxMemory` argument. After you call `ParseMultipartForm`, the file will be saved in the server memory with `maxMemory` size. If the file size is larger than `maxMemory`, the rest of the data will be saved in a system temporary file. You can use `r.FormFile` to get the file handle and use `io.Copy` to save to your file system.
@@ -69,11 +78,13 @@ We use three steps for uploading files as follows:
The file handler is the `multipart.FileHeader`. It uses the following struct: The file handler is the `multipart.FileHeader`. It uses the following struct:
```
type FileHeader struct { type FileHeader struct {
Filename string Filename string
Header textproto.MIMEHeader Header textproto.MIMEHeader
// contains filtered or unexported fields // contains filtered or unexported fields
} }
```
![](images/4.5.upload2.png?raw=true) ![](images/4.5.upload2.png?raw=true)
@@ -83,6 +94,7 @@ Figure 4.5 Print information on server after receiving file.
I showed an example of using a form to a upload a file. We can impersonate a client form to upload files in Go as well. I showed an example of using a form to a upload a file. We can impersonate a client form to upload files in Go as well.
```
package main package main
import ( import (
@@ -142,6 +154,8 @@ I showed an example of using a form to a upload a file. We can impersonate a cli
filename := "./astaxie.pdf" filename := "./astaxie.pdf"
postFile(filename, target_url) postFile(filename, target_url)
} }
```
The above example shows you how to use a client to upload files. It uses `multipart.Write` to write files into cache and sends them to the server through the POST method. The above example shows you how to use a client to upload files. It uses `multipart.Write` to write files into cache and sends them to the server through the POST method.