code for chapter 7 in javascript
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75
07_dijkstras_algorithm/javascript/01_dijkstras_algorithm.js
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75
07_dijkstras_algorithm/javascript/01_dijkstras_algorithm.js
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'use strict';
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// the graph
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const graph = {}
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graph["start"] = {}
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graph["start"]["a"] = 6
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graph["start"]["b"] = 2
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graph["a"] = {}
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graph["a"]["fin"] = 1
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graph["b"] = {}
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graph["b"]["a"] = 3
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graph["b"]["fin"] = 5
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graph["fin"] = {}
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// The costs table
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const costs = {};
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costs['a'] = 6
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costs['b'] = 2;
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costs['fin'] = Infinity;
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// the parents table
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const parents = {};
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parents['a'] = 'start';
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parents['b'] = 'start';
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parents['fin'] = null;
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let processed = [];
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function find_lowest_cost_node(costs) {
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let lowest_cost = Infinity;
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let lowest_cost_node = null;
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// Go through each node
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for (let node in costs) {
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let cost = costs[node];
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// If it's the lowest cost so far and hasn't been processed yet...
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if (cost < lowest_cost && (processed.indexOf(node) === -1)) {
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// ... set it as the new lowest-cost node.
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lowest_cost = cost;
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lowest_cost_node = node;
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}
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}
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return lowest_cost_node;
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}
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let node = find_lowest_cost_node(costs);
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while (node !== null) {
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let cost = costs[node];
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// Go through all the neighbors of this node
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let neighbors = graph[node];
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Object.keys(neighbors).forEach(function(n) {
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let new_cost = cost + neighbors[n];
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// If it's cheaper to get to this neighbor by going through this node
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if (costs[n] > new_cost) {
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// ... update the cost for this node
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costs[n] = new_cost;
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// This node becomes the new parent for this neighbor.
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parents[n] = node;
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}
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});
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// Mark the node as processed
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processed = processed.concat(node);
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// Find the next node to process, and loop
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node = find_lowest_cost_node(costs);
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}
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console.log("Cost from the start to each node:");
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console.log(costs); // { a: 5, b: 2, fin: 6 }
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