Add ES6 Examples to all chapters (#38)

* add ES6 example for binary search

* add ES6 example for selection sort

* add ES6 example for countdown

* add ES6 example for greet

* add ES6 example for factorial

* edit ES6 example for quicksort

* add ES6 example for loop sum

* add ES6 example for recursive sum

* add ES6 example for recursive count

* add ES6 example for recursive max

* add ES6 example for price of groceries

* add ES6 example for check voter

* add ES6 example for breadth-first search

* add ES6 example for dijkstras algorithm

* edit ES6 example for dijkstras algorithm

* edit ES6 example for set covering

* add ES6 example for longest common subsequence
This commit is contained in:
Yossi Adler
2017-11-13 18:12:59 +02:00
committed by Aditya Bhargava
parent 1a81d3e6b2
commit ec2890a93d
20 changed files with 328 additions and 18 deletions

View File

@@ -0,0 +1,72 @@
// the graph
const graph = {};
graph.start = {};
graph.start.a = 6;
graph.start.b = 2;
graph.a = {};
graph.a.fin = 1;
graph.b = {};
graph.b.a = 3;
graph.b.fin = 5;
graph.fin = {};
// The costs table
const costs = {};
costs.a = 6;
costs.b = 2;
costs.fin = Infinity;
// the parents table
const parents = {};
parents.a = 'start';
parents.b = 'start';
parents.fin = null;
let processed = [];
const findLowestCostNode = (itCosts) => {
let lowestCost = Infinity;
let lowestCostNode = null;
Object.keys(itCosts).forEach((node) => {
const cost = itCosts[node];
// If it's the lowest cost so far and hasn't been processed yet...
if (cost < lowestCost && (processed.indexOf(node) === -1)) {
// ... set it as the new lowest-cost node.
lowestCost = cost;
lowestCostNode = node;
}
});
return lowestCostNode;
};
let node = findLowestCostNode(costs);
while (node !== null) {
const cost = costs[node];
// Go through all the neighbors of this node
const neighbors = graph[node];
Object.keys(neighbors).forEach((n) => {
const newCost = cost + neighbors[n];
// If it's cheaper to get to this neighbor by going through this node
if (costs[n] > newCost) {
// ... update the cost for this node
costs[n] = newCost;
// This node becomes the new parent for this neighbor.
parents[n] = node;
}
});
// Mark the node as processed
processed = processed.concat(node);
// Find the next node to process, and loop
node = findLowestCostNode(costs);
}
console.log('Cost from the start to each node:');
console.log(costs); // { a: 5, b: 2, fin: 6 }