Make some rewordings

en/02.2.md

@@ -244,7 +244,7 @@ The reason that Go is concise because it has some default behaviors.
 
 ### array
 
-`array` is array obviously, we define them as follows.
+`array` is an array obviously, we define a one as follows.
 
 	var arr [n]type
 	
@@ -370,7 +370,7 @@ Attention: `append` will change the array that `slice` points to, and affect oth
 
 ### map
 
-`map` is behaves like a dictionary in Python. Use the form `map[keyType]valueType` to define it.
+`map` behaves like a dictionary in Python. Use the form `map[keyType]valueType` to define it.
 
 Let's see some code. The 'set' and 'get' values in `map` are similar to `slice`, however the index in `slice` can only be of type 'int' while `map` can use much more than that: for example `int`, `string`, or whatever you want. Also, they are all able to use `==` and `!=` to compare values.
 

en/02.3.md

@@ -151,23 +151,23 @@ In the fifth line, we put many values in one `case`, and we don't need to add th
 
 	integer := 6
 	switch integer {
-		case 4:
-			fmt.Println("integer <= 4")
-			fallthrough
-		case 5:
-			fmt.Println("integer <= 5")
-			fallthrough
-		case 6:
-			fmt.Println("integer <= 6")
-			fallthrough
-		case 7:
-			fmt.Println("integer <= 7")
-			fallthrough
-		case 8:
-			fmt.Println("integer <= 8")
-			fallthrough
-		default:
-			fmt.Println("default case")
+	case 4:
+		fmt.Println("integer <= 4")
+		fallthrough
+	case 5:
+		fmt.Println("integer <= 5")
+		fallthrough
+	case 6:
+		fmt.Println("integer <= 6")
+		fallthrough
+	case 7:
+		fmt.Println("integer <= 7")
+		fallthrough
+	case 8:
+		fmt.Println("integer <= 8")
+		fallthrough
+	default:
+		fmt.Println("default case")
 	}
 	
 This program prints the following information.
@@ -295,13 +295,13 @@ Let's see one example in order to prove what i'm saying.
     	fmt.Println("x = ", x)    // should print "x = 3"
 	}
 	
-Did you see that? Even though we called `add1`, and `add1` adds one to `a`, the value of `x` doesn't change.
+Can you see that? Even though we called `add1` with `x`, the origin value of `x` doesn't change.
 
 The reason is very simple: when we called `add1`, we gave a copy of `x` to it, not the `x` itself.
 
 Now you may ask how I can pass the real `x` to the function.
 
-We need use pointers here. We know variables are stored in memory and that they all have memory addresses. So, if we want to change the value of a variable, we must change the value at that variable's memory address. Therefore the function `add1` has to know the memory address of `x` in order to change its value. Here we pass `&x` to the function, and change the argument's type to the pointer type `*int`. Be aware that we pass a copy of the pointer, not copy of value.
+We need use pointers here. We know variables are stored in memory and they have some memory addresses. So, if we want to change the value of a variable, we must change its memory address. Therefore the function `add1` has to know the memory address of `x` in order to change its value. Here we pass `&x` to the function, and change the argument's type to the pointer type `*int`. Be aware that we pass a copy of the pointer, not copy of value.
 
 	package main
 	import "fmt"